跳到主要内容

東京大学 情報理工学系研究科 電子情報学専攻 2016年8月実施 専門 第2問

Author

Josuke

Description

Let us consider a falling-edge-triggered JK flip-flop as shown in Fig.1. This JK flip-flop is reset to (Q,Q)=(0,1)(Q,\overline{Q}) = (0,1) when RST=1RST = 1. Answer the following questions.

(1) Let us assume a 4-bit counter as shown in Fig.2, and the input signals shown in Fig.3 are given to the counter. Show a time chart of the outputs Q0Q3Q_0-Q_3. Here, let us assume that all the JJ and KK terminals are connected to 1, and the delay of each JK flip-flop, τ\tau , cannot be neglected.

(2) Modify the circuit in Fig.2 so that the outputs Q0Q3Q_0-Q_3 change simultaneously, and show its schematic. (Such a circuit is called a parallel counter or a synchronous counter.)

(3) Let us design a parallel decimal counter. A decimal counter is a circuit that starts counting from (Q3Q2Q1Q0Q_3Q_2Q_1Q_0) = (0000) up to (Q3Q2Q1Q0Q_3Q_2Q_1Q_0) = (1001) and then returns to (Q3Q2Q1Q0Q_3Q_2Q_1Q_0) = (0000) in the next state. Show a state transition diagram and a Karnaugh map of the counter.

(4) Show a schematic of a parallel decimal counter by using the results in (3).

(5) Modify the circuit in (2) to an up/down counter and show its schematic. An up/down counter is a counter whose operation mode can be changed either to count-up or count-down by a control signal UP/DOWNUP/\overline{DOWN}.

题目描述

考虑图 1 所示下降沿触发 JK 触发器。当 RST=1RST=1 时,触发器复位为 (Q,Q)=(0,1)(Q,\overline Q)=(0,1)。图 2、图 3 及所用符号均见上图,回答下列问题。

(1) 对图 2 的 44 位计数器输入图 3 所示信号,画出输出 Q0Q_0Q3Q_3 的时序图。假设所有 JJKK 端均接 11,且每个 JK 触发器的延迟 τ\tau 不可忽略。

(2) 修改图 2 的电路,使 Q0Q_0Q3Q_3 同时变化,并画出电路图。这种电路称为并行计数器或同步计数器。

(3) 设计一个并行十进制计数器:从 (Q3Q2Q1Q0)=(0000)(Q_3Q_2Q_1Q_0)=(0000) 计数到 (1001)(1001),下一状态返回 (0000)(0000)。画出其状态转移图和卡诺图。

(4) 利用 (3) 的结果,画出并行十进制计数器的电路图。

(5) 把 (2) 的电路改造成加/减计数器并画出电路图。该计数器通过控制信号 UP/DOWNUP/\overline{DOWN} 在向上计数和向下计数两种模式间切换。

Kai

(1)

(2)

(3)

Q3Q_3Q2Q_2Q1Q_1Q0Q_0Q3Q_3'Q2Q_2'Q1Q_1'Q0Q_0'
00000001
00010010
00100011
00110100
01000101
01010110
01100111
01111000
10001001
10010000

(4)

(5)