東京大学 情報理工学系研究科 電子情報学専攻 2015年8月実施 専門 第5問

标签：

• Tokyo-University
• Power-Spectrum-and-Parseval-Energy-Identity
• Parseval-Identity

Author

Josuke

Description

Let us denote the Fourier transform of the signal $f(t)$ as $F(\omega)$, where $t$ and $\omega$ represent a time variable and an angle frequency, respectively.

(1) Show the definition of the Fourier transform $F(\omega)$ of the signal $f(t)$. Also, explain the difference between the Fourier transform and the Fourier series expansion.

(2) Explain why $|F(\omega)|^2$ represents the power spectrum, i.e., the power at a certain angle frequency of $\omega$.

(3) Derive the following Parseval's theorem in the Fourier transform and determine $k$.

$$\int_{-\infty}^{\infty}|f(t)|^2\text{d}t = k\int_{-\infty}^{\infty}|F(\omega)|^2\text{d}\omega, k\text{ is a real constant.}$$

You may use $|f(t)|^2 = f(t)\overline{f(t)}$, $(\overline{f(t)} \text{ is the complex conjugate of }f(t))$. You may also use the Fourier transform of the following convolution integrals

$$\int_{-\infty}^{\infty}f(t - \tau)g(\tau)\text{d}r = k'\int_{-\infty}^{\infty}F(\omega)G(\omega)e^{j\omega t}\text{d}\omega ,$$

$j$ is the imaginary unit and $k'$ is a real constant.

You may include $k'$ when answering $k$.

(4) Explain the physical meaning of the Parseval's theorem in the Fourier transform.

Kai

(1)

$$F(\omega) = \int_{-\infty}^{\infty}f(t)e^{-j\omega t}\text{d}t$$

Fourier series can be applied to periodic signal. Fourier transform can be applied to non-periodic signal.

(2)

$$|F(\omega)|^2 = F(\omega)\overline{F(\omega)} = (\text{Real}\{F(\omega)\})^2 + (\text{Image}\{F(\omega)\})^2$$

Thus $|F(\omega)|^2$ represents the power of certain angle frequency $\omega$.

(3)

$$\begin{aligned} f(t) * g(t) &= \int_{-\infty}^{+\infty}f(t - \tau)g(\tau)\text{d}\tau = \int_{-\infty}^{+\infty}g(t - \tau)f(\tau)\text{d}\tau \\ f(0) * g(0) &= \int_{-\infty}^{+\infty}f(-\tau)g(\tau)\text{d}\tau = \int_{-\infty}^{+\infty}g(- \tau)f(\tau)\text{d}\tau \\ \end{aligned}$$

if $g(\tau) = \overline{f(-\tau)}$

$$\begin{aligned} G(\omega) &= \int_{-\infty}^{+\infty}g(t)e^{-j\omega t}\text{d}t \\ &= \int_{-\infty}^{+\infty}\overline{f(-t)}e^{-j\omega t}\text{d}t \\ \overline{G(\omega)} &= \int_{-\infty}^{+\infty}f(-t)e^{-j\omega t} \\ &= \int_{-\infty}^{+\infty}f(t)e^{-j\omega t}\text{d}t = F(\omega) \qquad G(\omega) = \overline{F(\omega)} \end{aligned}$$

So

$$\int_{-\infty}^{\infty}|f(t)|^2 = k'\int_{-\infty}^{\infty}|F(\omega)|^2 \text{d}\omega$$

(4)

The energy in time domain equals to $k'$ times energy in frequency domain.